equation for another curve

[montgomerys]

Im trying to make a curve which follows a cylinder. Its a cam curve. As the angle increases the displacement x increases up the cylinder. The angle is from 0 to 100. My X displacement distance is using this equation:


x=sqrt(0.04532-((angle^2)/326600)-(angle/7640))+0.2918


The dia of the cylinder is 1.13


Hope you can help.

 

[shankar_me]

Hi stephen montgomery,


I got a doubt. I used the euqation to generate a way the follower rises in the cam. The result is given bellow.





The brown line is the rise of the follower. I see almost zero rise in follower motion. That can be analyzed from your equation also. Also, there is an initial rise that present in the follower motion, if the follower motion is based on the equation that you gave. That results in a big zerk for the cam.


Regards,
Shankar

 

[jeff4136]

In cylindrical coordinates ...
r = 1.13 / 2
theta = 100 * t
z = your equation substituting "z" for "x" and "theta" for "angle"

 

[montgomerys]

Cool. Thanks Jeff. That looks correct.


Not sure where Shankar_me is getting the small displacement. Im getting 0.1727".


Thanks anyway lads. Problem solved.

 

[trillicomm]

I think PTC bought MathCad for simplifying the confusion in using ProE mathematical nutty notations.

 

[jeff4136]

> looks correct


Don't know if something like this will help with visualization (or is
in any way useful) or not, but ...
VSS on vector traj, section relation defining line length
sdX = sqrt(.04532 - (((100*trajpar)^2) / 326600) - (100 * trajpar/7640)) + .2918
2008-02-27_115354_vss-equation_sect_rel--wf2--.prt.zip


> nutty notations


What would a sane, function of t, notation look like?

 

[mcgowanp]

PTC simplifies!!!! Surely you jess!