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toriodal blend

manojnaik

New member
hi every body,



can any body help in modeling using toriadal blend.



I have made bush using toriodal blend. But I am not able to get the desired diameter.



can any body help me ??



thanks
 
G

Guest

Guest
Circumference = pi * radius^2,

or

C = pi*r^2 = pi*.25*dia^2



therefore,



the length of your part should be pi*.25*diameter^2.



If you wanted a diameter of 10, then the length would be 78.54.
 

hmt34

New member
hello friends,

I am facing a problem in toroidal bend when we need to specify the 2 parallel planes which defines the lenth or radius of the toroidal bend. how u people select the these parallel planes. And also any other applications of toridal bend besides Tyres.

thank you

Harsha.T.
 

ram

New member
dear harsha,

the two parallel planes must be parallel to the sketching plane.try it out.
 

salil

New member
Hi,



Select two end faces of the solid & try this on a protrusion like a plank dimensions 50x20x500 select two endfaces lengthwise.







Salil.
 
G

Guest

Guest
The two parallel planes are the two planes that will wrap around and meet each other to form a circle.
 

jrchrist

New member
Actually, the area formula of a circle is A=pi*rad^2. The curcumference formula is the first derivative of the area formula, or C=2*pi*rad, or C=pi*dia. (See, for example, Mark's Standard Handbook for Mechanical Engineers p. 2-8)



If you want a diameter of 10, then your length would be 31.416.



-James-
 
G

Guest

Guest
Doh! James is right. I don't know what I was thinking...



C=2*pi*radius

C=pi*diameter



radius = .5*C/pi

diameter = C/pi






Thanks James!
 

manojnaik

New member
Hi all,



My problem remains with me .



I have tried putting value pi*D



But my problem is that diameter what I am getting is nearer to the actual value but not exact.



NowI have made this component with spinal bend



Probably I have used this (toriodal bend) command for wrong

application??....



In that case what is the exact application of toridal bend??only for tire application??
 

hmt34

New member
hello all,

thank you friends, I have one problem helical sweeping along the non-linear trajectories. for example I want to model telephone cord which is a spring but its axis is not a stright line, it is a curve.

thank you

harsha
 

mjcole_ptc

New member
If you use Spinal Bend you can sketch the inner circle as two 180 deg arcs and you should get the right size inner diameter.
 

salil

New member
MjCole,





No need to draw in two steps this (360 deg.)can be achieved in one Spinal Bend feature only.Just try through

select curve.





Salil.
 

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