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Subject Topic: Convection Coefficient? Post ReplyPost New Topic
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hammerpe
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Posted: 02 January 2004 at 3:53pm | IP Logged Quote hammerpe

What is the Convection Coefficient (h) that is required for a convection boundry condition? What are it's units? I am using Pro/Mechanica Wildfire. I have a cylinder that has a heat load of 15 lbf/s applied to the inner surface. The outside of the cylinder is in stagnent air. I have my Convection Coefficient set to 100. I want to see how much I can improve cooling with adding some fins to the outside of the cylinder.

Also, I would've expected the max_dyn_temperature to have leveled out by 1000s but it doesn't. Even if I lower my heat load all the way to 1 lbf/s. The slope of the lines seems to stay the same, the max temp just keeps getting lower.

Thanks in advance!
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hammerpe
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Posted: 02 January 2004 at 6:31pm | IP Logged Quote hammerpe

Ok, so I downloaded a heatsink example from PTC's website. I followed all of the instructions and I do not get the same results as they do... They have a nice graph of their max_dyn_temperature leveling out after 1000s with a 100w input load. I must have units of somewhere I guess but I can't figure out where....

I have attached the heatsink file with all of my inputs. Here is the link to PTC...

http://www.ptc.com/cs/cs_24/howto/mth812/mth812.htm
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hammerpe
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Posted: 05 January 2004 at 8:33am | IP Logged Quote hammerpe

Just a FYI for anyone, I found this.....
http://www.tsdengineering.com/pages/HT_natural_conv.html

I haven't had time to apply this yet, will let you know the results. I'd still like to know why mt model doesn't match PTC's model....
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Luis Aguirre
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Posted: 05 January 2004 at 9:44pm | IP Logged Quote Luis Aguirre

Hello Hammerpe,

The values for the convection coefficient also known as the film coefficient are Btu/(hr*ft^2*F) or W/(m^2*K). Adding fins will definetely help to disipate more heat. If you still having problems later on post them I will see If I can fix them.

Luis
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JHardy
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Posted: 06 January 2004 at 6:40pm | IP Logged Quote JHardy

Hammerpe,

It sounds a little as if you have a units problem. You need to use consistent units throughout. Depending on your chosen units system, you need to make sure all parameters are in appropriate units; eg:

SI Metric:

Heat: Watts (or Joules/second)
Heat Flux: Watts/square metre
Temperature: Degrees Kelvin
Thermal Conductivity: Watts / metre / degree Kelvin
Specific Heat: Joules / kg / degree Kelvin
Convection: Watts / square meter / degree Kelvin

Inch / Pound / Second:

Heat: BTU
Heat Flux: BTU / second /square inch
Temperature: Degrees Fahrenheit
Thermal Conductivity: BTU / second / inch / degree Fahrenheit
Specific Heat: BTU / pound / degree Fahrenheit
Convection: BTU / second / square inch / degree Fahrenheit

Foot / Pound / Second:

Heat: foot . pound force
Heat Flux: foot . pound force / second /square foot
Temperature: Degrees Fahrenheit
Thermal Conductivity: foot . pound force / second / foot / degree Fahrenheit
Specific Heat: foot . pound force / slug / degree Fahrenheit
Convection: foot . pound force / second / square foot / degree Fahrenheit

Note that you may need to adjust the “catalogue data”, depending on your chosen units. Eg if you are using units of inch / pound / seconds, but your published data is in units of BTU / hour / square foot / degree Fahrenheit, you will need to allow an appropriate factor to convert to consistent units of BTU / second / square inch / degree Fahrenheit.

Some typical values of convection coefficient (in metric units) are:

Natural convection in air: 11 W/m2/K
Natural convection in water: 570 W/m2/K
Forced convection in air: 170 W/m2/K
Forced convection in water: 1,100 W/m2/K
Natural convection and boiling in water: 5,700 W/m2/K
Forced convection and boiling in water: 57,000 W/m2/K
Condensation of water at atmospheric pressure 5,700 W/m2/K

When considering convection from a surface, you may also need to consider emission or absorption from free surfaces as well.

Hope this helps.
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hammerpe
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Posted: 08 January 2004 at 5:47pm | IP Logged Quote hammerpe

It was my stupidity that was bringing me down. In mechanica the loads and constraints are automatically highlighted when you rin the simulation. In thermal they aren't, so I neede to highlight the boundry condition and it works perfectly.

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Mechwitch
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Posted: 15 November 2005 at 9:56am | IP Logged Quote Mechwitch

Hi all

I know this was all started a long time ago but I have recently been doing the same sort of thing. I've been looking for a realistic convection coefficient for forced convection in air and have come across the info above.

Do you have a reference for the above values so I can quote them in my report or details or link to where I can find them?

Thanks

MW

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